Difference between revisions of "$rand replacement script"
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;; so we now take the theoretical 1 and remove the 2 from before. 1-2 = -1 | ;; so we now take the theoretical 1 and remove the 2 from before. 1-2 = -1 | ||
;;You know have the random number you are looking for. | ;;You know have the random number you are looking for. | ||
− | + | ||
;;Check $1 is negative and $2 is positive | ;;Check $1 is negative and $2 is positive | ||
if ($1 < 0 && $2 >= 0) { | if ($1 < 0 && $2 >= 0) { |
Latest revision as of 19:42, 16 August 2006
mIRC has an inbuilt $rand identifier but there are a few errors that can occur from using $rand that you may not expect. Here's a list of changes this $rand2 identifier uses or fixes.
- Handle negative numbers.
- Fixes bug with mixture of numerical and alpha characters.
- If you pass only one parameter, it treats it as if you want to find a range between 0 and first parameter.
alias rand2 { ;;Make sure $rand2 is called and not /rand2 if (!$isid) { return $null } ;;check both $1 and $2 is a number to handle negative numbers and numbers with more then 1 char in them. if ($1 isnum && $2 isnum) { ;;When one of the parameters given is negative and the other parameter is posative we have to calculate the total amount of possible ;; results before we can attempt to find a random number. ;;To do this, we add the absolute value of the negative parameter (for -1 it would be 1 and -69 it would be 69 for example) to the positive parameter. ;;eg. ;; To find a random number from -2 to 1 we take the absolute of -2 (using $abs) which is 2 and add that to 1, 2+1 = 3 ;; -2,-1,0,1 which is the four possibilities we can have returned. ;; ;;Now we know there is four possibilities we can use the inbuilt $rand number to return a value. ;;Although we have a running total of 3 with 4 possible out comes, this is taken in to consideration when using $rand(0,3) ;;If we imagen $rand(0,3) returns a theoretical value of 1 we need to reduce this number by the amount of negative numbers we added before. ;; so we now take the theoretical 1 and remove the 2 from before. 1-2 = -1 ;;You know have the random number you are looking for. ;;Check $1 is negative and $2 is positive if ($1 < 0 && $2 >= 0) { ;;set %i to a random number between 0 and the total of $2 + the absolute value of $1 var %i = $rand(0,$calc($2 + $abs($1))) ;;return the random number music the absolute value of $1 return $calc(%i - $abs($1)) } ;;Exactly the same as the above except $2 being negative and $1 being the positive parameter elseif ($2 < 0 && $1 >= 0) { var %i = $rand(0,$calc($1 + $abs($2))) return $calc(%i - $abs($2)) } ;;If both parameters are negative, find the absolute value of the parameters and find a random number between those. ;;Once we have the random number we can just return a negative value of the result from $rand. elseif ($1 < 0 && $2 < 0) { return - $+ $rand($abs($1),$abs($2)) } ;;If we get here both numbers are possitive numbers, just return default rand values. else { return $rand($1,$2) } } ;;If either or both of the parameters are not a numerical value, get the ascii value of both parameters find a random number inbetween and return the ;; charater that the random number represents. ;;This is to stop a bug in $rand which returns $null if you try and get a random char between a alpha and a numeric. ;;To get around this, we get the $asc value of the charectors find a random number between those two numbers and return the charector. elseif ($1 && $2) { return $chr($rand($asc($1),$asc($2))) } ;;If we dont have a second parameter but the first one is a number, take it that the first parameter given should be the second and first is 0. elseif ($1 isnum) { return $iif($1 < 0,-) $+ $rand(0,$abs($1)) } ;;We must not of been given two parameters or if only one given, must not of been a numerical. Return null. return $null }
Contributed by Albie |